Python is throwing some inconsistent error for a file reference inside the Project folder based on 'Working Directory' in the script configuration My Project Structure is
config_utils.py
f = ''
def config_init():
global f
txt_dir = '../files/sample.txt'
f = open(txt_dir, "r")
f = f.read()
mycode.py
import config_ru.config_utils as cu
cu.config_init()
print(cu.f)
On executing mycode.py, it throws the below error w.r.t "sample.txt" in "files" package
but if I change the Working directory of "my_code.py" in the script configuration from "level2" to "level1", mycode.py gets executed successfully
This is very weird because in both the cases the location of "sample.txt" remains unchanged and both the error and being forced to change the Working Directory seems to be unacceptable. Please clarify
The work-around is to get the path of the module you are in and apply the relative path of the resource file to that:
from pathlib import Path
f = ''
def config_init():
global f
p = Path(__file__).parent.absolute()
txt_dir = (p / '../files/sample.txt').resolve()
f = open(txt_dir, "r")
f = f.read()