Good afternoon. I have 2 vectors of unequal length
let names = vec!["Marie", "Jana", "Eva", "Anna"];
let surnames = vec!["Novakova", "Svobodova", "Novotna", "Dvorakova", "Kralova"];
How can I go through all the possible combinations of first and last names ?
Conditional 3 vector I want to get:
let gen_full_name = vec!["Marie Novakova", "Jana Novakova", "Eva Novotna", "Anna Novotna", "Jana Novakova", ...];
let names = vec!["Marie", "Jana", "Eva", "Anna"];
let surnames = vec!["Novakova", "Svobodova", "Novotna", "Dvorakova", "Kralova"];
let mut full_names = Vec::with_capacity(names.len() * surnames.len());
for name in &names {
for surname in &surnames {
full_names.push(format!("{} {}", name, surname));
}
}
println!("{:?}", full_names);
No unnecessary allocations required.