I am using Python 3.10 and Strawberry 0.139
Is there any way to refractor out like-terms to write less code for defining types?
Lets say I have two types in my schema
@strawberry.type
class Home(Address):
name: str
location: str
description: str
phone: int
@strawberry.type
class Business(Address):
name: str
fax: int
location: str
description: str
phone: int
Is there a way I can refractor out like terms in a class using the abc library. Note that I am not referring to interfaces where you have to write in the inherited code. Something like this:
from abc import ABC
class Contact(ABC):
location: str
description: str
phone: int
@strawberry.type
class Home(Address):
name: str
@strawberry.type
class Business(Address):
name: str
fax: int
Inherit from a base strawberry.type
. Unlike interfaces, the base type won't be in the schema (unless explicitly included).
@strawberry.type
class Contact:
location: str
description: str
phone: int
@strawberry.type
class Home(Contact):
name: str
@strawberry.type
class Business(Contact):
name: str
fax: int