I have 3 relational Django database tables and i want to display data in 'name_en' column in all the tables as labels, and 'id' in city table as value in Django MultipleChoiceField
| Example Table Structure |
Table 1 (province):
| id | name_en |name_ta |
| -------- | ---------- |---------- |
|1 | Western | - |
|2 | Central | - |
Table 2 (district):
| id | ForeignKey | Name_en |Name_ta |
| -------- | ----------- | ----------- |------- |
|1 | 2 | Kandy | - |
|2 | 1 | Colombo | - |
Table 3 (city):
| id | ForeignKey | Name_en |Name_ta |
| -------- | ----------- | ---------- |---------- |
|1 | 1 | Uduwela | - |
|2 | 2 | Homagama |- |
I want to display MultipleChoiceField in this format
<select>
<option value='1(city id)'>Western,Colombo,Homagama</option>
</select>
You could do something like this:
class CityForm(forms.Form):
cities = forms.MultipleChoiceField(
choices=[]
)
def __init__(self, *args, **kwargs):
cities = City.objects.all()
cities_list = []
for city in cities:
cities_list.append([city.id, '{0}, {1}, {2}'.format(
city.name_en,
city.district.name_en,
city.province.name_en
)])
super().__init__(*args, **kwargs)
self.fields['cities'].choices = cities_list
You loop over all the cities, get their district, and then get the district's province. Assuming a city can only have one district and a district can only have one province.