How to exclude every number that has 1 and print the rest that the user has inputted and match the inputted number with printed numbers?

I'm having trouble coding this program in JAVA

Ask the user an integer number then print 1 to n where is input number. if the number have a 1 skip that number and make sure match the length of n number to the output.

Example:

input: 22

output 2 3 4 5 6 7 8 9 20 22 23 24 25 26 27 28 29 30 32 33 34 35 - Total of 22 numbers

skipped all numbers with 1 and matched the length of the inputted numbers

I tried doing conditional statements, nested ifs and for loop but i failed and i badly need some lessons so i can understand the logic

you can do something like this:

import java.util.Scanner;

public class test {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter a number: ");
        int num = sc.nextInt();
        int count = 0;
        for (int i = 1; count < num; i++) {
            if (String.valueOf(i).contains("1")) {
                continue;
            }
            System.out.println(i);
            count++;
        }
        sc.close();
    }
}

Update:

If you do not want to use String.valueOf() you can go like this:

import java.util.Scanner;

public class test {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter a number: ");
        int num = sc.nextInt();
        int count = 0;
        for (int i = 1; count < num; i++) {
            int val = i;
            boolean hasOne = false;
            while (val > 0) {
                if (val % 10 == 1) {
                    hasOne = true;
                    break;
                }
                val = val / 10;
            }
            if (hasOne) {
                continue;
            }
            System.out.println(i);
            count++;
        }
        sc.close();
    }
}