I am using javascript trying to grep everything that is NOT the mac address and remove it. Here is an example of a string.
var x = "20:ce:c4:00:01:e6 VLAN_ID=0";
I am trying to remove the "VLAN_ID=0"
So the desired output would be:
var x ="20:ce:c4:00:01:e6"
I've used two different regexes for mac address:
const regex = /[0-9a-f]{1,2}([\\.:-])(?:[0-9a-f]{1,2}\1){4}[0-9a-f]+/;
const regex2 = /([0-9A-Fa-f]{2}[:-]){5}([0-9A-Fa-f]{2})|([0-9a-fA-F]{4}\\.[0-9a-fA-F]{4}\\.[0-9a-fA-F]{4})+/;
I've tried playing around with the ^ but no luck
Using x = x.replace(regex2, "");
It replaces everything that is the mac address leaving me with the output VLAN_ID=0
You can extract the result by accessing the first match like so:
var x = "20:ce:c4:00:01:e6 VLAN_ID=0";
const regex2 = /([0-9A-Fa-f]{2}[:-]){5}([0-9A-Fa-f]{2})|([0-9a-fA-F]{4}\\.[0-9a-fA-F]{4}\\.[0-9a-fA-F]{4})+/;
x = x.match(regex2)[0];
console.log(x)