Check if a filename has multiple '.'/periods in it

So I'm making a website and in one of the pages you can upload images.

I didn't think of this before when making my file upload function but files are allowed to have multiple . in them, so how can I differentiate between the "real" . and the fake . to get the filename and the extension.

This is my file upload function, which isn't especially relevant but it shows how I upload the files:

def upload_files(files, extensions, path, overwrite=False, rename=None):
    if not os.path.exists(path):
        os.makedirs(path)

    filepath = None
    for file in files:
        name, ext = file.filename.split('.')
        if ext in extensions or extensions == '*':
            if rename:
                filepath = path + rename + '.' + ext if path else rename + '.' + ext
            else:
                filepath = path + file.filename if path else file.filename

            file.save(filepath, overwrite=overwrite)
        else:
            raise Exception('[ FILE ISSUE ] - File Extension is not allowed.')

As you can see I am splitting the filename based on the . that is there but I now need to split it and figure out which . split pair is the actual pair for filename and extension, it also creates the issue of providing too many values for the declaration name, ext since there is a third var now at least.

Sounds like you are looking for os.path.splitext which will split your filename into a name and extension part

import os

print(os.path.splitext("./.././this.file.ext"))
# => ('./.././this.file', '.ext')