The title basically says it all.
Suppose I have an element which I want to change color on :hover
, but while clicked, I want it to switch back to its original color. So, I've tried this:
a:link, a:visited, a:active {
background: red;
}
a:hover {
background: green;
}
As it turns out, this doesn't work. After a lot of head-scratching, I realized that the :hover
state was overriding the :active
state. This was easily solved by this:
a:link, a:visited {
background: green;
}
a:hover {
background: red;
}
a:active {
background: green;
}
(I could combine the 1st rule with the 3rd one).
Here's the fiddle: http://jsfiddle.net/V5FUy/
My question: is this the expected behavior? As far as I understand this, the :active
state should always override the :hover
state, since the :active
state will almost always be accompanied with the :hover
state.
yes this is expected behavior,
lets take a look at another example. just adding two classes,
<ul>
<li class="item first">item</li>
<li class="item">item</li>
<li class="item">item</li>
<li class="item">item</li>
<li class="item last">item</li>
</ul>
here the class first also comes together with the class item. but if we declare our css in the wrong order that would not give the wanted behavior
.first { background: blue; }
.item { background: red; }
as you can see, the last matching selector will be used. it is the same as your example, no mather what is more logic, the 2 pseudo-classes are concidered equal, thus the same rules apply the last matching defenition wins.
edit
pseudoclasses are equals, it is the one defined last that wins! here is a jsFiddle that proves my point :link defined after :hover, :link wins (test) so, your statement of :hover overriding :link is wrong, its just the same like with :active, its all about the order.