So here is the question I am given , I need to tell the output :
#include <iostream>
using namespace std;
int main()
{
int x = 10;
int y = 20;
if(x++ > 10 && ++y > 20 ){
cout << "Inside if ";
} else{
cout << "Inside else ";
}
cout << x << “ “ << y;
}
The ans given is Inside else 11 20
I checked with complier this is the correct answer but according to me the answer should be Inside else 11 21
.
Why is this happening ? Why isn't the ++y part executing ?
I also tried y++ I still get same answer.
If the first operand of the logical AND (&&
) operator evaluates to false, the second operand is not evaluated, because the value of the expression is already known.
From the C++ 20 Standard (7.6.14 Logical AND operator)
1 The && operator groups left-to-right. The operands are both contextually converted to bool (7.3). The result is true if both operands are true and false otherwise. Unlike &, && guarantees left-to-right evaluation: the second operand is not evaluated if the first operand is false.
Also, the value of an expression with the post-increment operator is the value of its operand before incrementing.
From the C++ 20 Standard (7.6.1.6 Increment and decrement_
1 The value of a postfix ++ expression is the value of its operand...
So, in this if
statement:
if(x++ > 10 && ++y > 20 ){
the left operand of the logical AND operator x++ > 10
evaluates to false
. However, the side effect of the post-increment operator is applied to the variable x
. The second operand ++y > 20
is not evaluated.
So, the control will be passed to the else
statement, and within its sub-statement x
will be equal to 11
and y
will keep its original value 20
.