I'm using Griffel https://griffel.js.org/ for the first time and I am struggling to achieve this simple thing. By default this button is hidden and when the user hover's over the parent I want to make the child visible.
I am using React so I have this button component inside the parent div.
const styles = useStyles();
<div className={styles.userContainer}>
<Button className={styles.removeUserButton} />
</div>
CSS:
export const useStyles = makeStyles({
removeUserButton: {
display: 'none'
},
userContainer: {
backgroundColor: '#fefefe',
'&:hover': {
'& removeUserButton': {
display: 'inline-block'
}
}
}
})
I was not sure if it will know what the removeUserButton class is so I also tried by making it variable. So I added:
const removeUserClassName = 'removeUserButton';
on top of the file and then in CSS:
[removeUserClassName]: {
display: 'none'
},
userContainer: {
backgroundColor: '#fefefe',
'&:hover': {
[`& ${removeUserClassName}`]: {
display: 'inline-block'
}
}
}
But this still does not work. And in case you are wondering I have also tried the first piece of code by adding . before removeUserButton.
Has anyone used Griffel and knows how to handle this? Appreciate any guidance. Thank you!
Here is a sandbox I created: https://codesandbox.io/s/griffel-hover-issue-gwx1sj
The issue is that you are attempting to use a classname that is in your configuration (removeUserClassName
). Yet, Griffel uses dynamic class names. So you'll need to use a different selector.
You can see the nature of the dynamic class names in this playground example.
Here is a working StackBlitz that uses the button
as selector rather than class name and it works fine.
Here is the code for reference:
import { makeStyles } from '@griffel/react';
export const useStyles = makeStyles({
removeUserButton: {
display: 'none',
},
userContainer: {
width: '150px',
height: '50px',
backgroundColor: 'black',
':hover': {
'& button': { display: 'inline-block' },
backgroundColor: 'blue',
},
},
});