I declared a few geometric figures types such as:
typedef struct s_sphere{
t_tuple origin;
double radius;
} t_sphere;
typedef struct s_cylinder{
t_tuple origin;
double height;
double radius;
} t_cylinder;
typedef struct s_triangle{
t_tuple A;
t_tuple B;
t_tuple C;
} t_triangle;
etc...
Now, I would like to declare an intersection type which will contain two doubles and a geometric figure. I will then store all my intersections in a chained list:
// I do not know what type to give to geometric_figure
typedef struct s_intersection{
double t1;
double t2;
// what_type geometric_figure;
} t_intersection;
typedef struct s_intersection_list{
t_intersection intersection;
struct s_intersection_list *next;
} t_intersection_list;
I could use void* geometric_figure
but I would like to avoid the most mallocs possible.
Is there a handy way of getting where I want without allocating geometric_object ?
type which will contain two doubles and a geometric figure.
Consider union
with an identifier.
typedef struct s_intersection{
double t1;
double t2;
int id; // some id to know what type follows
union {
t_sphere sph;
t_cylinder cyl;
t_triangle tri;
} u;
} t_intersection;
If t_intersection
is to be allocated, consider a flexible member array to right size the allocation.
typedef struct s_intersection{
double t1;
double t2;
int id; // some id to know what type follows
union {
t_sphere sph;
t_cylinder cyl;
t_triangle tri;
} u[]; // FAM
} t_intersection;
Example: allocate a triangle.
t_intersection *p = malloc(sizeof *p + sizeof p->u[0].tri);