I know the string in c will be terminated by a character \0.
However, if I do char a[5]="abcd\n" , where would \0 be?
Or do I need to reserve at least one position for \0, whenever I try to use char[] to store a string?
Thank you for any help!
You should do:
char a[]="abcd\n";
without specifying the size to let compiler figure out the buffer size. The actual buffer will have size of 6 to accommodate your 5 bytes + 1 byte for terminating zero. When you type "something" without assignment, compilaer puts that string in a dedicated place in the program with at least 1 zero byte after the last character.
Writing char a[5]="abcd\n" is a bad practice because it will cause functions like strcpy() to act in undefined manner as your variable 'a' is not a c string, but just a buffer of characters, which by chance seem to be all printable/visible + terminating \n