Continue to match next case after match?

I have a match case that I want to execute even if a previous statement already matched.

Here's what I currently have:

key: Literal['all', 'a', 'b'] = 'a'

def do_a():
    pass
def do_b():
    pass

match key:
    case 'a':
        do_a()
    case 'b':
        do_b()
    case 'all':
        do_a()
        do_b()

Is there any way to simplify the code so I can remove the case 'all'?

Something like

match key:
    case 'a' | 'all':
        do_a()
    case 'b' | 'all':
        do_b()

Example Setup:

from typing import Literal
key: Literal['all', 'a', 'b']

def do_a():
    print('do_a')
    
def do_b():
    print('do_b')

Solution I: You can just use if:

if key in ('a', 'all'):
    do_a()
if key in ('b',  'all'):
    do_b()

Solution II: You could use a function mapper, like so:

function_mapper = {
    'all': (do_a, do_b),
    'a': (do_a,),
    'b': (do_a,),
}

key = 'all'
for func in function_mapper[key]:
    func()