How come that in the following snippet
int a = 7;
int b = 3;
double c = 0;
c = a / b;
c
ends up having the value 2, rather than 2.3333, as one would expect. If a
and b
are doubles, the answer does turn to 2.333. But surely because c
already is a double it should have worked with integers?
So how come int/int=double
doesn't work?
This is because you are using the integer division version of operator/
, which takes 2 int
s and returns an int
. In order to use the double
version, which returns a double
, at least one of the int
s must be explicitly casted to a double
.
c = a/(double)b;