Get bounding box of SVG drawing

I would like to extract the bounding box of a SVG drawing.

Since Python is already available on the system and also used to perform other tasks, I don't want to use JavaScript or any other language. My understanding is if the bounding box of a single element can be calculated (but I don't know how).

The bounding box of the whole drawing is just the minimum and maximum x,y values a of all elements, hence probably the bounding boxes of all elements need to be calculated.

I am a Python beginner, but svgwrite is probably not the right module and so far I was scared by the installation of rsvg on a Windows system.

There may be a more direct approach to achieve this, but something like this should meet your requirements.

You can convert your file to a list of path objects with the svg2paths method and iterate through them.

from svgpathtools import svg2paths

def get_bbox(svg_file):
    paths, _ = svg2paths(svg_file)

    for i, path in enumerate(paths):
        if i == 0:
            # Initialise the overall min-max with the first path
            xmin, xmax, ymin, ymax = path.bbox()
        else:
            # Expand bounds to match path bounds if needed
            p_xmin, p_xmax, p_ymin, p_ymax = path.bbox()
            xmin = min(xmin, p_xmin)
            xmax = max(xmax, p_xmax)
            ymin = min(ymin, p_ymin)
            ymax = max(ymax, p_ymax)
    
    print(xmin, xmax, ymin, ymax)

get_bbox("myfile.svg")