Get a file from path where file name LIKE

I am developing a WordPress that utilises gulp to build the frontend of the application (scss, js) files.

In my functions.php I am using enqueue to load my css and js so that they can be used in the editor.

add_action( 'enqueue_block_editor_assets', function() {
   wp_enqueue_style( 'editor-styling', get_theme_file_uri( '/dist/styles/main.css', __FILE__) );
   wp_enqueue_script( 'editor-scripts', get_theme_file_uri( '/dist/scripts/main.js', __FILE__) );

} );

Running running a simple gulp command I can do the above as the file will be named main.css. However, I am facing an issue that when I use gulp --production the style and javascript are suffixed with a random value.

For example my main.scss will (once I run the above command) turn into main-9acd4829.css.

My question is, how can I get a file from a certain directory where file name like main<whatever>.css.

I have tried using something such as

get_theme_file_uri(glob('/dist/styles/main*.css'), __FILE__)

However that returned null

I guess you have to check yourself in the different folders, inspired by the code of get_theme_file_uri, something like this (note that glob returns an array while get_theme_file_uri takes a string):

add_action( 'enqueue_block_editor_assets', function() {
    $style_file = glob(get_stylesheet_directory() . '/dist/styles/main*.css');
    if(!$style_file || !count($style_file)){
        $style_file = glob(get_template_directory_uri() . '/dist/styles/main*.css');
    }
    //NOTE: you can use foreach if your glob returns multiple files and this is what you want
    //NOTE2: in theory you could skip the use of get_theme_file_uri here because you already tested in which folder it is, this is just an example
    if($style_file && count($style_file)){
        wp_enqueue_style( 'editor-styling', get_theme_file_uri( '/dist/styles/' . $style_file[0], __FILE__) );
    }
    
    $script_file = glob(get_stylesheet_directory() . '/dist/scripts/main*.js');
    if(!$script_file || !count($script_file)){
        $script_file = glob(get_template_directory_uri() . '/dist/scripts/main*.js');
    }
    //NOTE: you can use foreach if your glob returns multiple files and this is what you want
    //NOTE2: in theory you could skip the use of get_theme_file_uri here because you already tested in which folder it is, this is just an example
    if($script_file && count($script_file)){
        wp_enqueue_script( 'editor-scripts', get_theme_file_uri( '/dist/scripts/' . $script_file[0], __FILE__) );
    }
} );