pythonpdfplumber

pdfplumber python extract_tables setting for the specific strategy

i've this pdf, I'm trying to extract table from pdf. Wwhat is the better strategy to get the table? I can not be able to get the value specific on table , for example in the first table , i 've to get [70,75,80,85,90,100,105,110,115,120] and for the second line [0,0,2,6,10,10,10,2,2,0,0]

My final result would be : 411924,KGDHN,MBELT W 40 INT, T.GG SUPREME/SELLERIA, 9643 BEIGE EBONY/COCOA, [70,75,80,85,90,100,105,110,115,120] ,[0,0,2,6,10,10,10,2,2,0,0],42,200.00,8,400.00

enter image description here

with pdfplumber.open(doc) as pdf:
print(pdf.pages)
page = pdf.pages[0]
im = page.to_image(resolution = 400)
text = page.extract_words()
im = im.draw_rects(page.extract_words())
im.show()
# h = open('empty_test' + '.json', "w")
# json.dump(text, h, indent=2, sort_keys=False)
# h.close()

enter image description here

It is a PDF with text. I can extract the text easily, and keep the layout almost the same

for page in pdf.pages:
    for line in page.extract_text(keep_blank_chars=False, layout=True).splitlines():
        print(line)

enter image description here

Solution

  • The idea is to isolate the smallest area around the values via cropping:

    enter image description here

    You can then use the x0 position of each word as your vertical line.

    enter image description here

    You can pass the lines to table settings via explicit_vertical_lines which will give back empty strings for the "blank" cells.

    col1.extract_text()='406831 DJ20N\n1000 NERO'
MBELT W.40 GG MAR DOLLAR PIGPRINT
['60', '65', '70', '75', '80', '85', '90', '95', '100', '105', '110', '115', '120']
['', '', '0', '0', '2', '6', '10', '10', '10', '2', '2', '', '']
col3.extract_text()='42 218.00 9,15\n9,156.0'

col1.extract_text()='414516 0YA0G\n1000 BLACK'
MBELT W.30 GG MAR. PLUTONE CALF
['65', '70', '75', '80', '85', '90', '95', '100', '105', '110', '115', '120', '135']
['0', '0', '0', '2', '6', '15', '15', '15', '2', '2', '0', '0', '']
col3.extract_text()='57 205.00 11,6\n11,685.0'

col1.extract_text()='406831 0YA0G\n1000 BLACK'
MBELT W.40 GG MAR PLUTONE CALF
['60', '65', '70', '75', '80', '85', '90', '95', '100', '105', '110', '115', '120']
['', '', '', '', '', '2', '2', '2', '2', '2', '1', '', '']
col3.extract_text()='11 218.00 2,39\n2,398.0'

col1.extract_text()='627055 92TIN\n9769 B.EBONY/NERO'
MBELT W.37GG M.R T.GG SUPREME/PLUTONE CALF
['60', '65', '70', '75', '80', '85', '90', '95', '100', '105', '110', '115', '120']
['', '', '', '', '', '3', '3', '3', '3', '3', '1', '', '']
col3.extract_text()='16 244.00 3,90\n3,904.0'

    There are various ways you could approach this, but the steps I've used here are:

    These are the horizontal lines we can use to split into rows:

    enter image description here

    These are the vertical lines we can use to divide the columns:

    enter image description here

    import itertools

# First thick horizontal line that span > width % of page
product_line = next(
    line for line in page.horizontal_edges 
    if  line['orientation'] == 'h'
    and line['linewidth'] > 1 
    and line['width'] > page.width / 1.25
)

# Search for Description 
description = page.search('Description/Size Quantity Qty Price Value')
has_description = len(description) > 0

# If there is a description we crop there, else we use the line divider
if has_description:
    description = description[0]
    product_area_top = description['bottom'] + 10
    product_area = page.crop(
        (product_line['x0'], product_area_top, product_line['x1'], page.height)
    )
else:
    product_area_top = product_line['top']
    product_area = page.crop(
        (product_line['x0'], product_area_top, product_line['x1'], page.height)
    )

# find horizontal lines for rows
hlines = [
    line['top'] for line in product_area.edges 
    if  line['orientation'] == 'h'
    and line['stroking_color'] == (0, 0, 0) 
    and line['width'] > product_area.width / 1.25
]

# If there is no description on the page we need to add in the top as the first line (in order to extract row 1)
if has_description is False:
    hlines = [product_area_top] + hlines

# Make sure our lines are sorted from top -> bottom
hlines = sorted(set(hlines))

for top, bottom in itertools.pairwise(hlines):
    row = product_area.crop(
        (product_area.bbox[0], top, product_area.width, bottom)
    )

    # vertical lines to create columns
    vlines = [
       line['x0'] for line in row.vertical_edges 
       if line['object_type'] == 'line'
    ]

    # we need to add an end line to extract last column
    vlines = sorted(vlines + [row.width])

    col1 = row.crop((vlines[0], top, vlines[1], bottom))
    col2 = row.crop((vlines[1], top, vlines[2], bottom))
    col3 = row.crop((vlines[2], top, vlines[3], bottom))
    
    lines = col2.extract_text_lines()

    # lines 1-2 are the values, use their positions to crop 
    bbox = lines[1]['x0'], lines[1]['top'], lines[-1]['x1'], lines[-2]['bottom']

    values = col2.crop(bbox)

    # use start of each word as a vertical line edge
    vlines = [word['x0'] for word in values.extract_words()]

    table = values.extract_table(dict(
       explicit_vertical_lines = vlines
    ))

    print(f'{col1.extract_text()=}')
    print(lines[0]['text'], table[0], table[1], sep='\n')
    print(f'{col3.extract_text()=}')

    You may be able to extract the other values simply from the text extraction methods, or you could use a similar cropping technique on col1, col3.