[SOLVED] regex - multiple line and multiple content

regex - multiple line and multiple content

I'm looking for a pattern that match with

    "changes": [
      "5.12.0",
      "5.14.0"
    ],
...
    "changes": [
      "1",
      "5.0.0",
      "5.10.1"
    ],
...
    "changes": [
      "4.4",
      "5.0.0",
      "5.10.1"
    ],

I'm no expert, I've tried maybe 40 or 50 different solutions, here's my last try:

/"changes": \[\s*("([0-9](.+))*"(,+))*\s*\],/

i try this one and it works, ty.

"changes": \[\s*("([0-9](.+))*"(,+)\s )+("([0-9](.+))*"\s)\],

Solution

I would do it in two steps:

Search for the list of versions between the brackets after "changes":

/"changes":\s*\[\s*([^\]]+)\s*\]/g : https://regex101.com/r/XHaxJ0/4
For each match, you'll get the list of versions in the capturing group 1:
```
"4.4",
      "5.0.0",
      "5.10.1"
```
You can then extract each version with /[\d.]+/g : https://regex101.com/r/XHaxJ0/2

The Javascript code:

const input = `    "changes": [
      "5.12.0",
      "5.14.0"
    ],
...
    "changes": [
      "1",
      "5.0.0",
      "5.10.1"
    ],
...
    "changes": [
      "4.4",
      "5.0.0",
      "5.10.1"
    ],`;

const regexChangesContent = /"changes":\s*\[\s*([^\]]+)\s*\]/g;
const regexVersion = /[\d.]+/g;

// To fill with the found versions in the changes arrays.
let versions = [];

let matchChangesContent,
    matchVersion;

while ((matchChangesContent = regexChangesContent.exec(input)) !== null) {
  while ((matchVersion = regexVersion.exec(matchChangesContent[1])) != null) {
    versions.push(matchVersion[0]);
  }
}

console.log(versions);

EDIT since question has changed

As you just want to delete the "changes" entries, I would do the following:

const input = `    "changes": [
      "5.12.0",
      "5.14.0"
    ],
    "date": "01.01.2023",
    "changes": [
      "1",
      "5.0.0",
      "5.10.1"
    ],
    "property": "value",
    "should_stay": true,
    "changes": [
      "4.4",
      "5.0.0",
      "5.10.1"
    ],`;

const regexChanges = /"changes":\s*\[\s*[^\]]+\s*\]\s*,/g;

console.log(input.replace(regexChanges, ''));