I want to count the days in a month whose day or night data is not equal to 0 or letters.
A | B | C | D | E | F | G | H | |
---|---|---|---|---|---|---|---|---|
1 | Monday | Monday | Tuesday | Tuesday | Wednesday | Wednesday | Thursday | Thursday |
2 | Day | Night | Day | Night | Day | Night | Day | Night |
3 | n/a | 10 | n/a | 0 | 5 | 5 | 10 | blanc |
In 3rd row, if in a day, daytime or nighttime is not a letter or 0, than that day counts 1. So, the result of the above example should be 3. (monday + wednesday + thursday)
This is the long form of the formula.
=IF(OR(AND(ISNUMBER(A3)=TRUE;A3>0);AND(ISNUMBER(B3)=TRUE;B3>0));1;0)+
IF(OR(AND(ISNUMBER(C3)=TRUE;C3>0);AND(ISNUMBER(D3)=TRUE;D3>0));1;0)+
IF(OR(AND(ISNUMBER(E3)=TRUE;E3>0);AND(ISNUMBER(F3)=TRUE;F3>0));1;0)+
IF(OR(AND(ISNUMBER(G3)=TRUE;G3>0);AND(ISNUMBER(H3)=TRUE;H3>0));1;0)
I could solve with countif or sumproduct if there weren't two conditions for a day, but I couldn't count with two conditionals.
Thank you in advance!
Try using the following formula:
• Formula used in cell I3
=SUM(--(UNIQUE(FILTER(A1:H1,(A3:H3<>"")*(A3:H3<>0)*(NOT(ISTEXT(A3:H3)))),1)<>""))
Or,
• Formula used in cell I3
=SUM(N(UNIQUE(FILTER(A1:H1,ISNUMBER(A3:H3)*(A3:H3>0)),1)<>""))
None of the solutions returns error, if there is no non zero number:
Update:
• Formula used in cell I3
=SUMPRODUCT(IFERROR((ISNUMBER(A3:H3)*(A3:H3>0))/
COUNTIFS(A3:H3,">0",$A$1:$H$1,$A$1:$H$1),0))