Implement the Filter method on a Prototype

I have to filter a prototype without using the .filter method. I thought that I had it, but it gave me a mistake in one of the tests, I checked the answer, but I don't fully understand it and when i searched for it, my answer is the only one that appears.

Write your own Array.prototype.myFilter(), which should behave exactly like Array.prototype.filter(). You should not use the built-in filter method. The Array instance can be accessed in the myFilter method using this.

This is the Prop:

Array.prototype.myFilter = function(callback) {
  const newArray = [];
  // Only change code below this line

  // Only change code above this line
  return newArray;
};

This is the answer they need:

for(let i = 0; i < this.length; i++){
  if(Boolean(callback(this[i], i, this)) === true){
  newArray.push(this[i])
  }
}

This is the answer i came up with:

for(let i = 0; i < this.length; i++){
  if(callback(this[i]){
  newArray.push(this[i])
  }
}

This are the Tests:

Passed:[23, 65, 98, 5, 13].myFilter(item => item % 2) should equal [23, 65, 5, 13].
Passed:["naomi", "quincy", "camperbot"].myFilter(element => element === "naomi") should return ["naomi"].
Failed:[1, 1, 2, 5, 2].myFilter((element, index, array) => array.indexOf(element) === index) should return [1, 2, 5].
Passed:Your code should not use the filter method.`

I don't understand this part

(this[i], i, this)

The callback for Array#filter accepts three arguments:

• element the current element
• index the index of the element
• array the array being iterated on

What is asked of you is to make myFilter behave exactly like filter. Therefore you cannot omit these arguments when calling the user's predicate:

for(let i = 0; i < this.length; i++){
  if(callback(this[i], i, this)){
    newArray.push(this[i])
  }
}