casciiebcdic

C code to convert EBCDIC printables to ASCII in-place


What is the simplest way in C to convert an EBCDIC-encoded string to its ASCII equivalent in-place.

The only characters that need to be converted are the space, alphanumerics, and from the set <=>()+-*/&|!$#@.,;%_?". All other characters can simply be replaced with ..

The function signature will basically be:

void ebcdicToAscii (char *s);

At the moment, I'm leaning towards a series of lookup tables and multiple if statements for the various EBCDIC sections, but I wonder if there's a better way.


Solution

  • Using the table from here, from the top of my head:

    static const unsigned char e2a[256] = {
              0,  1,  2,  3,156,  9,134,127,151,141,142, 11, 12, 13, 14, 15,
             16, 17, 18, 19,157,133,  8,135, 24, 25,146,143, 28, 29, 30, 31,
            128,129,130,131,132, 10, 23, 27,136,137,138,139,140,  5,  6,  7,
            144,145, 22,147,148,149,150,  4,152,153,154,155, 20, 21,158, 26,
             32,160,161,162,163,164,165,166,167,168, 91, 46, 60, 40, 43, 33,
             38,169,170,171,172,173,174,175,176,177, 93, 36, 42, 41, 59, 94,
             45, 47,178,179,180,181,182,183,184,185,124, 44, 37, 95, 62, 63,
            186,187,188,189,190,191,192,193,194, 96, 58, 35, 64, 39, 61, 34,
            195, 97, 98, 99,100,101,102,103,104,105,196,197,198,199,200,201,
            202,106,107,108,109,110,111,112,113,114,203,204,205,206,207,208,
            209,126,115,116,117,118,119,120,121,122,210,211,212,213,214,215,
            216,217,218,219,220,221,222,223,224,225,226,227,228,229,230,231,
            123, 65, 66, 67, 68, 69, 70, 71, 72, 73,232,233,234,235,236,237,
            125, 74, 75, 76, 77, 78, 79, 80, 81, 82,238,239,240,241,242,243,
             92,159, 83, 84, 85, 86, 87, 88, 89, 90,244,245,246,247,248,249,
             48, 49, 50, 51, 52, 53, 54, 55, 56, 57,250,251,252,253,254,255
    };
    
    void ebcdicToAscii (unsigned char *s)
    {
        while (*s)
        {
            *s = e2a[(int) (*s)];
            s++;
        }
    }
    

    For your specific requirements, I would suggest something like:

    #include <stdio.h>
    
    void inSituEbcdicToAscii (char *s) {
        static char etoa[] =
            "                                "
            "                                "
            "           .<(+|&         !$*); "  // first char here is real space
            "-/         ,%_>?         `:#@'=\""
            " abcdefghi       jklmnopqr      "
            "  stuvwxyz                      "
            " ABCDEFGHI       JKLMNOPQR      "
            "  STUVWXYZ      0123456789      ";
    
        while (*s != '\0') {
            *s = etoa[(unsigned char)*s];
            s++;
        }
    }
    
    int main (void) {
        char str[] = "\xc8\x85\x93\x93\x96\x40\xa3\x88\x85\x99\x85\x5a";
        inSituEbcdicToAscii (str);
        printf ("%s\n", str);
        return 0;
    }
    

    which outputs Hello there! from the equivalent EBCDIC characters. All other characters beyond those you showed an interest in are converted to a space, though you can change that to something else (make sure you don't modify EBCDIC code 0x40 which is the real space).