A boy starts counting using her left hand’s fingers. The counting sequence is like 1-thumb, 2-index finger, 3-middle finger, 4-ring finger, 5-little finger then in the reverse order like 6-ring finger, 7-middle finger, 8-index finger, 9 thumb. Then again 10-index finger and so on. The program must print the last finger used for counting for a given value of N. The fingers names are thumb, index, middle, ring and little.
I found the answer for thumb finger, index finger and the little finger. But I couldnt find the patter for the index and the ring finger. below is the code that i have tried.
import java.util.*;
public class Hello {
public static void main(String[] args) {
//Your Code Here
Scanner sc=new Scanner(System.in);
long n=sc.nextInt();
if(n%8 == 1) System.out.print("thumb");
else if(n%8 == 5) System.out.print("little");
else if(n%4 == 3) System.out.print("middle");
else {
// logic for index and ring finger.
}
}
}
someone please help me to finish the logic.
As mentioned by @dawood-ibn-kareem to use ||
; you can use it something like:
import java.util.*;
public class Hello {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
long n = sc.nextInt();
if (n % 8 == 1) {
System.out.print("thumb");
} else if (n % 8 == 5) {
System.out.print("little");
} else if (n % 4 == 3) {
System.out.print("middle");
} else if (n % 8 == 2 || n % 8 == 0) {
System.out.print("index");
} else if (n % 8 == 4 || n % 8 == 6) {
System.out.print("ring");
}
}
}