Solve Algebraic Equation in SQL

I would like to use SQL to solve an algebraic equation for market share solving for the quantity of Product 1 to achieve a target market share.

Data:

Target: 35%

Equation: ([Product 1 Quantity] * [Target]) / (([Product 1 Quantity] * [Target]) + ([Product 2] + Product 3] + [Product 4]))

Let x = Target, A = Product 1 Qty, B = sum(Product 2 Quantity, Product 3 Quantity, Product 4 Quantity)

Ax/(Ax+B) = 0.35 or 300x / (300x + 700) = 0.35

1. Simplify:

   3x / 3x + 7 = 0.35

2. Multiply both sides by 3x+7:

   3x = 0.35(3x + 7)

3. Multiply both sides by 100

   300x = 35(3x + 7)

4. Expand 35(3x + 7)

   300x = 105x +245

5. Move to left

   195x = 245

6. Solve

   x = 49/39

Current: Product 1 has a quantity of 300 of the 1,000 total quantity or 30%. What I am trying to solve, what is the total additional quantity needed of Product 1 to achieve 35%? Keep in mind an increase of Product 1 also increases the total quantity.

How can this be solved using MSSQL? Any other suggestions? Greatly appreciate any help! Thank you.

Here's a slighly different version:

DECLARE @target NUMERIC(9,2) = 0.35
,   @A INT
,   @B INT
,   @TARGET_COEFF NUMERIC(19, 9)

SELECT  @A = MAX(CASE WHEN Product = 'Product1' THEN Quantity END)
,   @B = SUM(CASE WHEN Product <> 'Product1' THEN Quantity END)
FROM
(
    VALUES  (N'Product1', 300)
    ,   (N'Product2', 200)
    ,   (N'Product3', 200)
    ,   (N'Product4', 300)
    ,   (N'Total', 1000)
) t (Product,Quantity)
WHERE   Product <> 'Total'

/*
Ax / (Ax + B) = 0.35

Ax = 0.35 * Ax + B * 0.35

Ax - 0.35Ax = B * 0.35

0.65Ax = B * 0.35

x = B * @target / (( 1 - @target) * A)

*/
SELECT  @TARGET_COEFF = @B * @target / ((1 - @target) * @A)

SELECT  @TARGET_COEFF AS coeff, @A * @TARGET_COEFF AS new_quantity, @A * @TARGET_COEFF - @A AS needed
,   @A * @TARGET_COEFF / (@B + @A * @TARGET_COEFF) AS verification

I included inside the transformation of the equation so you get x by itself as well as some verification. Most important thing is that you transform your equation correctly.

Output: