pythonwsgiwsgiref

How to catch POST using WSGIREF


I am trying to catch POST data from a simple form.

This is the first time I am playing around with WSGIREF and I can't seem to find the correct way to do this.

This is the form:
<form action="test" method="POST">
<input type="text" name="name">
<input type="submit"></form>

And the function that is obviously missing the right information to catch post:

def app(environ, start_response):
    """starts the response for the webserver"""
    path = environ[ 'PATH_INFO']
    method = environ['REQUEST_METHOD']
    if method == 'POST':
        if path.startswith('/test'):
            start_response('200 OK',[('Content-type', 'text/html')])
            return "POST info would go here %s" % post_info
    else:
        start_response('200 OK', [('Content-type', 'text/html')])
        return form()

Solution

  • You should be reading responses from the server.

    From nosklo's answer to a similar problem: "PEP 333 says you must read environ['wsgi.input']."

    Tested code (adapted from this answer):
        Caveat: This code is for demonstrative purposes only.
        Warning: Try to avoid hard-coding paths or filenames.

    def app(environ, start_response):
        path    = environ['PATH_INFO']
        method  = environ['REQUEST_METHOD']
        if method == 'POST':
            if path.startswith('/test'):
                try:
                    request_body_size = int(environ['CONTENT_LENGTH'])
                    request_body = environ['wsgi.input'].read(request_body_size)
                except (TypeError, ValueError):
                    request_body = "0"
                try:
                    response_body = str(request_body)
                except:
                    response_body = "error"
                status = '200 OK'
                headers = [('Content-type', 'text/plain')]
                start_response(status, headers)
                return [response_body]
        else:
            response_body = open('test.html').read()
            status = '200 OK'
            headers = [('Content-type', 'text/html'),
                        ('Content-Length', str(len(response_body)))]
            start_response(status, headers)
            return [response_body]