SQL Delete specific rows based on date and criteria

I've got a table that has duplicate data that needs to be cleaned up. Consider the following example:

CREATE TABLE #StackOverFlow
(
    [ctrc_num] int, 
    [Ctrc_name] varchar(6),
    [docu] bit, 
    [adj] bit, 
    new bit, 
    [some_date] datetime
);
    
INSERT INTO #StackOverFlow
    ([ctrc_num], [Ctrc_name], [docu], [adj], [new], [some_date])
VALUES
    (12345, 'John R', null, null, 1, '2023-12-11 09:05:13.003'),
    (12345, 'John R', 1, null, 0, '2023-12-11 09:05:12.987'),
    (12345, 'John R', null, null, 1, '2023-12-11 09:05:12.947'),
    (56789, 'Sam S', null, null, 1, '2023-12-11 09:05:13.003'),
    (56789, 'Sam S', null, null, 1, '2023-12-11 09:05:12.987'),
    (56789, 'Sam S', 1, null, 0, '2023-12-11 09:05:12.947'),
    (78945, 'Pat P', null, null, 1, '2023-12-11 09:05:13.003'),
    (78945, 'Pat P', null, null, 1, '2023-12-11 09:05:12.987'),
    (78945, 'Pat P', null, null, 1, '2023-12-11 09:05:12.947');

This gives me:

[ctrc_num]  [Ctrc_name] [docu]  [adj]   [new]   [some_date]
-----------------------------------------------------------------------
12345        John R     NULL    NULL    1       2023-12-11 09:05:13.003
12345        John R     1       NULL    0       2023-12-11 09:05:12.987
12345        John R     NULL    NULL    1       2023-12-11 09:05:12.947
56789        Sam S      NULL    NULL    1       2023-12-11 09:05:13.003
56789        Sam S      NULL    NULL    1       2023-12-11 09:05:12.987
56789        Sam S      1       NULL    0       2023-12-11 09:05:12.947
78945        Pat P      NULL    NULL    1       2023-12-11 09:05:13.003
78945        Pat P      NULL    NULL    1       2023-12-11 09:05:12.987
78945        Pat P      NULL    NULL    1       2023-12-11 09:05:12.947

What I need to do is delete from the table duplicates. If new is 0, delete the records where new is 1. If all records have new = 1 keep the newest record and delete the older ones.

The result should look like this:

[ctrc_num]  [Ctrc_name] [docu]  [adj]  [new]    [some_date]
-----------------------------------------------------------------------
12345        John R     1       NULL    0       2023-12-11 09:05:12.987
56789        Sam S      1       NULL    0       2023-12-11 09:05:12.947
78945        Pat P      NULL    NULL    1       2023-12-11 09:05:13.003

I've tried ROW_NUMBER:

;WITH RankedByDate AS
(
    SELECT 
        ctrc_num, Ctrc_name,
        docu, adj, new, some_date,
        ROW_NUMBER() OVER (PARTITION BY Ctrc_num, Ctrc_name, [docu],[adj], [new] 
                           ORDER BY some_date DESC) AS rNum
    FROM 
        #StackOverFlow
)
SELECT * 
FROM RankedByDate

This separates the ones with new = 0, but I still have the ones with new = 1 that are ordered.

Grouping gives me the records that are duplicated but no way to delete the ones needed to be deleted:

SELECT [ctrc_num]
    ,[Ctrc_name]
    ,[docu]
    ,[adj]
    ,[new]
FROM 
    #StackOverFlow
GROUP BY 
    [ctrc_num]
    ,[Ctrc_name]
    ,[docu]
    ,[adj]
    ,[new]
HAVING 
    COUNT(*) > 1

Break the problem down into it's parts

1. "If new is 0, delete the records where new is 1"

   delete from #StackOverFlow
   where [new] = 1
   and [ctrc_num] in (select [ctrc_num]
                      from #StackOverFlow
                      where [new] = 0);
   

2. "If all records have new = 1 keep the newest record and delete the older ones" Use a CTE to add a row number based on the date and partitioned by the [ctrc_num] such that the "first" record in each group is the one you want to keep - if there is only 1 row in a group that's the one you want to keep anyway. Then delete everything else

   ;with cte as
   (
       select 
            [ctrc_num]  
            ,ROW_NUMBER() OVER (PARTITION BY [ctrc_num] ORDER BY [ctrc_num], [some_date] DESC) as rw
       from #StackOverFlow
   )
   DELETE FROM cte where rw <> 1;