Python : printing a list (concatenated by 2 lists) shows " " or ' '

I make a list named scramble. This list is created by randomly adding the values of 2 lists (move1 and move2)

When I print the list, the answer are surrounded by " " or ''.

exemple :

scramble = ['U', 'F2', 'B', 'R2', "U'", 'R', "R'", 'D', 'L2', 'B2', "U'", 'R2', "R'", 'F', "D'"]

my code:

import random as rd

scramble = []
move1 = ["F","R","L","U","B","D"]
move2 = ["","'","2"]

while len(scramble) < 15:
    s = move1[rd.randint(0, 5)]
    t = move2[rd.randint(0, 2)]
   
    scramble.append(s+t) 

I really want to understand why it happens.

and then, correct it.

I suppose that they are several ways to clean the "" and '' after the list is created. But :

1. I found that this solution is not optimal.
2. I also want that the "move1" is not repeated with the last one. I was planning to work with .startwith but my problem is that ti's sometimes starts with " and sometimes with '.

I finally found the solution. Well, I still don't know why printing the scramble list gave me a mix of " and ' but print(.joint) seems to work.

Thanks to everyone.

import random as rd

scramble = []
move1 = ["F","R","L","U","B","D"]
move2 = ["","'","2"]

# generate the first move to compare with the next ones :
s = rd.choice(move1)
t = rd.choice(move2)
scramble.append(s+t)


# generate the next 14 ones and do not tolerate the same "move1" next to each other (using "startswith" method):
for i in range(1,15):
    n = len(scramble)
    s = rd.choice(move1)
    t = rd.choice(move2)
    if scramble[n-1].startswith(s) :
        pass
    else :
        scramble.append(s+t)



# show the result, with spaces
print("  ".join(scramble))