qtqtableviewqsqltablemodel

Select QTableView row from a model index

In my Qt 6.6.0 application I set up a QSqlTableModel and a QTableView with sorting enabled:

QSqlTableModel *model;
model = new QSqlTableModel(this, db);
model->setTable("table");
model->setEditStrategy(QSqlTableModel::OnManualSubmit);
model->sort(0, Qt::AscendingOrder);
model->select();

ui->tableDb->setModel(model); // QTableView

I add a record in this way:

QSqlRecord record = model->record();
record.setValue("col1", value1);
// ...

for (int i = 0; i < record.count(); i++) record.setGenerated(i, true);
bool ret = true;
ret &= _model->insertRecord(-1, record);
ret &= _model->submitAll();
if (!ret) return false;

ui->tableDb->selectRow(???);

I want to select the row of the last inserted record. Since I have sorting enabled, I don't know where the record is placed in the QTableView.

How to retrieve its "visual" position from the model index?

Looking at the QTableView docs I found nothing relevant. There is a scrollTo() function but it just ensures the record is visible, not selected. I'm looking for something like a QTableView::selectRow(const QModelIndex &index) function...

Solution

  • I had to use a QSortFilterProxyModel:

    QSqlTableModel *model;
QSortFilterProxyModel *proxyModel;

model = new QSqlTableModel(this, db);
model->setTable("table");
model->setEditStrategy(QSqlTableModel::OnManualSubmit);
model->select();

proxyModel = new QSortFilterProxyModel(this);
proxyModel->setSourceModel(model);
proxyModel->sort(0);
ui->tableDb->setModel(proxyModel);

// ...

QModelIndex index = proxyModel->mapFromSource(model->index(model->rowCount() - 1, 0));
ui->tableDb->selectionModel()->setCurrentIndex(index, QItemSelectionModel::SelectCurrent | QItemSelectionModel::Rows);

    In this way I can retrieve the correct QModelIndex of the QTableView from the index of the QSqlTableModel.