How to move a specific value to the end of the array without affecting the order of other elements?

Suppose I have an array of [0,7,4,0,0,8,3,0,0,0,5,6] and I have to take all the zeroes to last positions after other numbers without modifying their order. So the output array should be like : [7,4,8,3,5,6,0,0,0,0,0];

How will i get the desired result output using Java 8 , can anyone please suggest

I have tried using the following code

public class ZeroLast {

    public static void main(String[] args) {
        List<Integer> list = Arrays.asList(0,7,4,0,0,8,3,0,0,0,5,6);
        list.sort(Comparator.reverseOrder());
        System.out.println(list);
    }
}

And the output is : [8, 7, 6, 5, 4, 3, 0, 0, 0, 0, 0, 0]

And i know this is because using reverseOrder() mthod it will sort the elements using Descending order and this is not the desired output what it should be . so anything i will do here to get the output or can you please give sample code logic part to get the results and Thanks.

you can use sort method on your list with a custom comparator to do it.

List<Integer> list = Arrays.asList(0,7,4,0,0,8,3,0,0,0,5,6);
list.sort((o1, o2) -> o1 == 0 ? 1 : (o2 == 0 ? -1 : 0));
System.out.println(list);

Using this all 0s must be at the end of the List without modifying any other order.