[SOLVED] LuaU - Need to make this efficient, don't want to spam elseifs

LuaU - Need to make this efficient, don't want to spam elseifs

Okay, so, I'm just curious on how to make this more efficent. I know it likely has something to do with a table loop like in pairs() or something. I know this is bad code, and I want to find a way to make it not bad.

if string.find(subject.Name, 0) then
    inVal.Value = 0
elseif string.find(subject.Name, 1) then
    inVal.Value = 1
elseif string.find(subject.Name, 2) then
    inVal.Value = 2
elseif string.find(subject.Name, 3) then
    inVal.Value = 3
elseif string.find(subject.Name, 4) then
    inVal.Value = 4
elseif string.find(subject.Name, 5) then
    inVal.Value = 5
elseif string.find(subject.Name, 6) then
    inVal.Value = 6
elseif string.find(subject.Name, 7) then
    inVal.Value = 7
elseif string.find(subject.Name, 8) then
    inVal.Value = 8
elseif string.find(subject.Name, 9) then
    inVal.Value = 9
end

Solution

You can parse the int value from the string using string.match and then use tonumber function on it.

This would be more efficient then looping every possible answer.

local match = string.match(subject.Name, "%d")
inVal.Value = tonumber(match)