I have 2 lists. I want to find the elements in ls2 where any element of ls1 is a substring. I would like to return a list of ls2 elements along with the substring that was searched and found from ls1
ls1 = ['apple','banana','pear']
ls2 = ['strawberry is not here',
'blueberry is over there',
'the pear tree is not ready yet',
'we have lots of pear trees',
'apples are yummy']
Both of these return a partial answer
[ls1[j] for j in range(len(ls1)) if any(ls1[j] in x for x in ls2)] # returns elements from ls1 alone
[i for i in ls2 if any(w in i for w in ls1)] # returns elements from ls2 alone
What I would like is to see:
[('the pear tree is not ready yet','pear'),
('we have lots of pear trees','pear'),
('apples are yummy','apple')]
Get rid of the any aggregation and just do nested loops:
result = [(sentence, word)
for sentence in ls2 for word in ls1
if word in sentence]
Alternatively, use itertools.product to get the same effect as the nested loops:
import itertools
result = [(sentence, word)
for sentence, word in itertools.product(ls2, ls1)
if word in sentence]