Here's the code example:
res = []
for i in game.keys():
for j in game.keys():
if f'{i}{j}' not in res and f'{j}{i}' not in res:
res.append(f'{i}{j}')
print(res)
I need this, but it should work for not only 2, but 3, 4, 5, 6 and 7 arguments (I wonder if there's a function that returns this and takes arguments like permutation and combination, so function(table_Of_Arguments, number_Of_Elements)
). I could write my own function in the above way, but I think there should already be something like that.
I've done some research and many people recommend permutation
or combination
from itertools
, but permutation
returns too much (it returns both {i}{j} and {j}{i}) and combination
returns too little (it doesn't return cases where i==j
). I will be using it with table_Of_Arguments
of size 32, so I hope there is something more optimized than my code, because 32^7 is a pretty high number.