Flutter Force State to have certain Mixin

I have a mixin (MyMixin) that I apply in the state of some widgets like this:

    class MyStfulWidget extends StatefulWidget {
      @override
      _MyStfulWidget State createState() => _MyStfulWidget State();
    }
    
    class _MyStfulWidget State extends State<MyStfulWidget> with MyMixin { ... }

I sometimes need to pass this stateful widgets as a parameter for a method (MyMethod)

    void myMethod(Widget myWidget) { ... }

The problem with the following method is that it accepts every kind of widgets. If I pass a widget that does not have a MyMixin it will not work properly...

Is there any way to force the "myWidget" parameter to be a stateful widget that contains a mixin in its state?

Thanks for the help!

The way I ended up achieving this was to create a new abstract class MyMixinWidget that extends a Stateful Widget, which in turn forces the createState() to return a new abstract class MyMixinState that extends State with MyMixin.

abstract class MyMixinWidget extends StatefulWidget {
  const MyMixinWidget({Key? key}) : super(key: key);

  @override
  MyMixinState createState();
}

abstract class MyMixinState<T extends MyMixinWidget> extends State<T> with MyMixin {
}

So it can be implemented like this

class MyWidget extends MyMixinWidget {
  const MyWidget({Key? key}) : super(key: key);

  @override
  MyMixinState<MyWidget> createState() => _MyWidgetState();
}

class _MyWidgetState extends MyMixinState<MyWidget> {
  @override
  Widget build(BuildContext context) {
    return const Placeholder();
  }
}