I have sample code of a function in which uses pattern matching to match a string value containing wildcards with an actual string value.
def isMatch(text, pattern):
n = len(text)
m = len(pattern)
i = 0
j = 0
startIndex = -1
match = 0
while i < n:
if j < m and (pattern[j] == '?' or pattern[j] == text[i]):
i += 1
j += 1
elif j < m and pattern[j] == '*':
startIndex = j
match = i
j += 1
elif startIndex != -1:
j = startIndex + 1
match += 1
i = match
else:
return False
while j < m and pattern[j] == '*':
j += 1
return j == m
s = "RE340T6-1MCWW"
p = "RE340T*-*****"
if isMatch(s, p):
print("Yes")
else:
print("No")
In this sample code, the string (s) "RE340T6-1MCWW" matches the pattern (p), "RE340T*-*****" and returns a "Yes", as it should.
What I want to do is using the above function,have a list of strings and find the matches in a list of strings with wildcards. For example:
s = ['GUC 40 410','HUC 40 410','XUC 40 410']
p = ['GUC 40 4**','HUC 40 4**','XUC 40 4**']
I don't know how to insert looping through the lists in the function to return where the string (s) matches the pattern (p). Any ideas for the next step?
If I just substitute the list for the static string, it just returns a "No"
You can simply use another _find method to check for isMatch():
def isMatch(text, pattern):
n, m = len(text), len(pattern)
i, j = 0, 0
startIndex = -1
match = 0
while i < n:
if j < m and (pattern[j] == '?' or pattern[j] == text[i]):
i += 1
j += 1
elif j < m and pattern[j] == '*':
startIndex = j
match = i
j += 1
elif startIndex != -1:
j = startIndex + 1
match += 1
i = match
else:
return False
while j < m and pattern[j] == '*':
j += 1
return j == m
def _find(S, ps):
res = []
for i, s in enumerate(S):
for j, p in enumerate(ps):
if isMatch(s, p):
res.append((i, j))
return res
s = ['GUC 40 410', 'HUC 40 410', 'XUC 40 410']
p = ['GUC 40 4**', 'HUC 40 4**', 'XUC 40 4**']
print(_find(s, p))
[(0, 0), (1, 1), (2, 2)]