Summary
I'm obtaining an error when running a bash script via cron. The script errors out when it reaches the following command; keep in mind that the bash script swaps out ${END_DATE} with the date the script was run:
python -c "import shutil; shutil.make_archive('packages/weekly-report-${END_DATE}', 'zip', 'output/${END_DATE}/')"
Error produced (line 53 is what I posted above):
line 53: python: command not found
Cron settings (python snippet is located in the bash script):
m h dom mon dow command
5 3 * * 1 /data/run-WP046-cronjob.sh
Shebang for bash script: #!/bin/bash
What I've Tried
I do not get this error when running the script as my profile. Python successfully imports shutil & zips my desired directory. Has anyone experienced this? I've looked online and can't find similar problem examples.
Please let me know if I'm missing needed information for this question.
As John Bollinger pointed out the full path to the executable needed to be specified. I update the script to point to it and error has been corrected. Thank you comment section! Script update below:
/usr/bin/python -c "import shutil; shutil.make_archive('packages/weekly-report-${END_DATE}', 'zip', 'output/${END_DATE}/')"