First off, I apologize if I am using wrong terminologies on this question. Hopefully, I can come through with the details.
I am trying to send files
(local images) and embed
using the command await channel.send(files=files, embed=embedvar)
and the output normally is like this:
current_output
The images are above the embed.
What I would like to know is if there is a way to have the images below the embed? Basically, to run the embed
argument first then the files
argument using a single await channel.send()
I saw this post regarding .send()
being a promise and using .then()
to separate the embed
then files
but I have no way to check and implement this without learning JavaScript. I did try to implement it using JS to PY packages but I think I have to mess with the transfer of data using stuff like JSON. I am hoping as well for direction if this is possible to implement and try in the Python language by itself.
Discord.js send file after embed
Snippet of the code:
embedvar = discord.Embed(title=f'🔗 {name}', description=text, url=link)
embedvar.set_author(name=user, icon_url=img)
embedvar.add_field(name="", value="", inline=True)
embedvar.set_footer(text=f'Posted on: Requested by:')
files = []
for filename in os.listdir(path):
file_path = os.path.join(path, filename)
files.append(discord.File(file_path, filename))
channel = bot.get_channel(*channel)
await channel.send(files=files, embed=embedvar)
Thank you.
The Javascript code in the snippet is sending 2 messages. You can do the same in Python simply like this:
await channel.send(embed=embedvar)
await channel.send(files=files)
As far as I know, it's not possible to choose the order of images/embed in a single message, so you have to send 2 separate messages.