shellcommand-line-arguments

Shell how to pass only some user input to script?

If I have a very simple shell script like this:

echo "thing 1?"
read input1
echo $input1

echo "thing 2?"
read input2
echo $input2

How can I call the script/command with only 1 of the user inputs provided, while allowing any subsequent reads calls to prompt my terminal? I have been doing printf "foo\n" | sh myscript.sh which does pass in the 1st read, but then when it get's to the 2nd, instead of prompting the user the script just exits.

Solution

  • Use cat to read from standard input.

    ( echo foo; cat ) | sh myscript.sh