In the game "No Man's Sky Expedition 14", these are the jump distances from the starting system R0 to the five rendezvous systems R1 thru R5. If R0 is (0,0,0) and R1 is (105,0,0) and R4 is in the x-y plane, what are the coordinates for R2 thru R5?
R0 -> R1 105 ly
R0 -> R2 259 ly
R0 -> R3 360 ly
R0 -> R4 33 ly
R0 -> R5 235 ly
R1 -> R2 255 ly
R1 -> R3 373 ly
R1 -> R4 76 ly
R1 -> R5 187 ly
R2 -> R3 251 ly
R2 -> R4 269 ly
R2 -> R5 201 ly
R3 -> R4 370 ly
R3 -> R5 229 ly
R4 -> R5 225 ly
Turns out that I can't say that P4 is in the x-y plane because that makes P2 unsolvable. So I don't know how to approach this. Any help appreciated.
Take any three systems
R0 -> R1 : 105
R0 -> R2 : 259
R1 -> R2 : 255
that form the three sides of a triangle.
Then use the cosine rule to find the angles between each of two sides
and then use the distances and angles to find (x,y) coordinates. This is just a polar to cartesian conversion.