How to remove default namespace xmlns using XSLT?

I have a XML file having default namespace xmlns="http://www.xxxx.com/xyz" and target namespace xmlns:tns="http://www.xxxx.com/xyz" , Both need to be removed

<?xml version="1.0" encoding="UTF-8" ?>
<Root xmlns:tns="http://www.xxxx.com/xyz" xmlns="http://www.xxxx.com/xyz">
    <Header type="XXXX" purpose="Original" xmlns="">
        <ID>XXXXXX</ID>
    </Header>
</Root>

I use the below code but it doesn't remove the default namespace xmlns="http://www.xxxx.com/xyz" from the root element

   <xsl:template match="*">
    <!-- remove element prefix -->
    <xsl:element name="{local-name()}">
      <!-- process attributes -->
      <xsl:for-each select="@*">
        <!-- remove attribute prefix -->
        <xsl:attribute name="{local-name()}">
          <xsl:value-of select="."/>
        </xsl:attribute>
      </xsl:for-each>
      <xsl:apply-templates/>
    </xsl:element>
  </xsl:template>

Can anyone help to suggest how to solve this case?

XML image for your reference

If you want to remove the default namespace then you cannot put the renamed elements back into their original namespace.

Seeing that the attributes in your example are not in a namespace (as is most often the case), I believe you could do simply:

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

<xsl:template match="*">
    <xsl:element name="{local-name()}">
        <xsl:copy-of select="@*"/>
        <xsl:apply-templates/>
    </xsl:element>
</xsl:template>

</xsl:stylesheet>

Demo here.