const a= [1,2,3,4,5,6,7,8,9,10];
function evenNum (a){
for (let element of a){
if (element%2===0){
console.log(element);
}
}
};
console.log(oddNum());
function oddNum (a){
for (let element of a){
if (element%2!=0){
console.log(element);
}
}
};
console.log(evenNum([1,2,3,4,5,6,7,8,9,10]))
Learning javascript as a complete beginner to programming in general. As I was following this video text in this "exercise" we wanted to display only the odd and even numbers in the array.
While the second function works ok, I don't understand why can't I declare an array before the evenNum
function and use the array as a parameter of the next function.
Was expecting the same results as the function below.
This is the problem:
function evenNum (a) {
This function definition declares a
as a local function parameter, so it is NOT the same variable as the global array that is also named a
.
It will probably be easier to understand if you give the function parameter a different name than the global array.
This is also a problem:
console.log(oddNum());
You defined the oddNum()
function to require a parameter, and yet you are calling it without a parameter.