In Python, can I round all printed floats with a single command?

I am working with a Python script that prints many floating point numbers. Within each print command, I use round(x, 3) to round the printed number x to 3 decimal places before printing. Here is a simplified example:

x1 = 1.61803398875
print('x1 = ' + str(round(x1, 3)))  # x1 = 1.618
x2 = x1**2
print('x2 = ' + str(round(x2, 3)))  # x2 = 2.618
x3 = 1/(x2-1)
print('x3 = ' + str(round(x3, 3)))  # x3 = 0.618

The actual code contains hundreds of these print commands. Is there a more efficient way to perform the rounding part of this script? For example, is there a single overarching command that will round all printed floats to a given precision, as there is for numpy and pandas variables?

I am looking for a solution that does not involve moving or combining the print commands or converting the printed variables to numpy and pandas variables before printing.

Solution

Using f-strings is a much easier way to specify rounding in string representations of numbers:

x1 = 1.61803398875
print(f'x1 = {x1:.3f}')  # x1 = 1.618
x2 = x1**2
print(f'x2 = {x2:.3f}')  # x2 = 2.618
x3 = 1/(x2-1)
print(f'x3 = {x3:.3f}')  # x3 = 0.618

but you do still need to repeat the .3f part each time.

If you wanted to DRY as much as possible, you could write a wrapper:

def print_var(var: str, val: float) -> None:
    print(f'{var} = {val:.3f}')


x1 = 1.61803398875
print_var('x1', x1)  # x1 = 1.618
x2 = x1**2
print_var('x2', x2)  # x2 = 2.618
x3 = 1/(x2-1)
print_var('x3', x3)  # x3 = 0.618

or you could redefine print (I wouldn't recommend this one, personally):

import builtins

def print(*args, **kwargs):
    rounded_args = [
        f'{arg:.3f}' if isinstance(arg, float) else arg
        for arg in args
    ]
    builtins.print(*rounded_args, **kwargs)


x1 = 1.61803398875
print('x1 = ', x1)  # x1 = 1.618
x2 = x1**2
print('x2 = ', x2)  # x2 = 2.618
x3 = 1/(x2-1)
print('x3 = ', x3)  # x3 = 0.618