In index.tsx
in this backbone example,
I have a function:
const useInfiniteMutations: <TData, TPage, TParams>(...: {
getNextPageParam?: (lastPageParam: TPage | undefined) => TPage | undefined;
mutationFn: (variables: { pageParam: TPage } & TParams) => Promise<TData>;
onSuccess?: (data: TData) => void;
}) => void
And when I pass arguments to the parameters:
type MyVariables = {
name: string;
};
const { mutate } = useInfiniteMutations({
getNextPageParam: (lastPageParam = -1) => lastPageParam + 1,
mutationFn: async ({
name,
pageParam,
}: MyVariables & { pageParam: number }) => {
const result = { name, pageParam };
return result;
},
});
and I found this weird type inference:
const useInfiniteMutations: <{
name: string;
pageParam: number;
}, number, MyVariables & {
pageParam: number;
}>
which results the following error:
const variables: MyVariables = {
name: "foo",
};
mutate(variables); // Property 'pageParam' is missing in type 'MyVariables' but required in type '{ pageParam: number; }'.typescript(2345)
Why TParams
is not inferred as MyVariables
? How can I make it?
I researched a lot and tried a lot of approaches that I've learned so far, but none of them worked...
This is the full minimal reproducible example:
import { useEffect, useState } from "react";
export const useInfiniteMutations = <TData, TPage, TParams>({
getNextPageParam,
mutationFn,
onSuccess,
}: {
getNextPageParam?: (lastPageParam: TPage | undefined) => TPage | undefined;
mutationFn: (variables: { pageParam: TPage } & TParams) => Promise<TData>;
onSuccess?: (data: TData) => void;
}) => {
const [params, setParams] = useState<TParams>();
const [nextPageParam, setNextPageParam] = useState<TPage>();
const mutate = (newParams: TParams) => {
const newNextPageParam = getNextPageParam?.(undefined);
if (newNextPageParam === undefined) {
return;
}
setNextPageParam(newNextPageParam);
setParams(newParams);
};
useEffect(() => {
if (params === undefined || nextPageParam === undefined) {
return;
}
mutationFn({
...params,
pageParam: nextPageParam,
}).then((data) => {
onSuccess?.(data);
});
}, [nextPageParam]);
return {
mutate,
};
};
export function demo() {
type MyVariables = {
name: string;
};
const { mutate } = useInfiniteMutations({
getNextPageParam: (lastPageParam = -1) => lastPageParam + 1,
mutationFn: async ({
name,
pageParam,
}: MyVariables & { pageParam: number }) => {
const result = { name, pageParam };
return result;
},
});
const variables: MyVariables = {
name: "foo",
};
mutate(variables); // Property 'pageParam' is missing in type 'MyVariables' but required in type '{ pageParam: number; }'.typescript(2345)
}
TypeScript doesn't generally perform surgery on intersection types when inferring generic type arguments. If you have a generic function parameter whose type is T & Y
(where T
is a generic type parameter) and you pass in an argument of type Z
which is equivalent to X & Y
, TypeScript is very likely to infer T
to be the entire type Z
and not just X
.
That's because
X & X & Y
is equivalent to X & Y
So it's unlikely that you can "make" TypeScript infer the type you wanted for TParams
in your example. In situations like this, it's more useful to just allow TypeScript to infer the type the way it does, and then you can explicitly de-intersect it yourself using something like the Omit<T, K>
utility type.
So your current function looks like this:
declare const useInfiniteMutations:
<TData, TPage, TParams>({ getNextPageParam, mutationFn, onSuccess }: {
getNextPageParam?: (lastPageParam: TPage | undefined) => TPage | undefined;
mutationFn: (variables: { pageParam: TPage } & TParams) => Promise<TData>;
onSuccess?: (data: TData) => void;
}) => {
mutate: (newParams: TParams) => void;
}
But we need to change it to the following:
declare const useInfiniteMutations:
<TData, TPage, TParams>({ getNextPageParam, mutationFn, onSuccess }: {
getNextPageParam?: (lastPageParam: TPage | undefined) => TPage | undefined;
mutationFn: (variables: { pageParam: TPage } & TParams) => Promise<TData>;
onSuccess?: (data: TData) => void;
}) => {
mutate: (newParams: Omit<TParams, "pageParam">) => void;
}
See how the newParams
parameter of mutate
is of type Omit<TParams, "pageParam">
, so even if TypeScript infers a type with a pageParam
property for TParams
, the mutate
function won't need that property. So your call with work:
mutate(variables); // okay
As for the implementation of useInfiniteMutations
, you'll need to change some occurrences of TParams
to Omit<TParams, "pageParam">
, and then anywhere you were relying on TParams & {pageParam: TPage}
to be equivalent to Omit<TParams, "pageParam"> & {pageParam: TPage}
, you'll need to use a type assertion, because TypeScript can't see higher order generic type equivalences like that. See microsoft/TypeScript#28884 for more information.
So your implementation might look like
export const useInfiniteMutations = <TData, TPage, TParams>({
getNextPageParam,
mutationFn,
onSuccess,
}: {
getNextPageParam?: (lastPageParam: TPage | undefined) => TPage | undefined;
mutationFn: (variables: { pageParam: TPage } & TParams) => Promise<TData>;
onSuccess?: (data: TData) => void;
}) => {
const [params, setParams] = useState<Omit<TParams, "pageParam">>();
const [nextPageParam, setNextPageParam] = useState<TPage>();
const mutate = (newParams: Omit<TParams, "pageParam">) => {
const newNextPageParam = getNextPageParam?.(undefined);
if (newNextPageParam === undefined) {
return;
}
setNextPageParam(newNextPageParam);
setParams(newParams);
};
useEffect(() => {
if (params === undefined || nextPageParam === undefined) {
return;
}
mutationFn({
...params as TParams, // <-- this is a white lie
pageParam: nextPageParam,
}).then((data) => {
onSuccess?.(data);
});
}, [nextPageParam]);
return {
mutate,
};
};
where the params as TParams
is needed to convince TypeScript that the resulting object is of the expected type.