How to export module name to functions launched as a process?

I have two functions myFunc() and myOtherFunc() defined in two different files: generic.py and no_choice.py with two different implementations. I import them as follows into main.py:

main.py:

if __name__=="__main__":
    config = input()
    if config=="generic":
        import generic as myfile
    else:
        import no_choice as myfile

Two functions use this import. fun1() and fun2() defined in main.py.

main.py:

def fun1():
  # Do some processing
  myfile.myFunc()

def fun2():
  # Do some processing
  myfile.myOtherFunc()

Then, I use multiprocessing to launch these two functions as parallel processes, as follows:

main.py -> within if __name__=="__main__"::

fun1task = multiprocessing.Process(target=fun1)
fun2task = multiprocessing.Process(target=fun2)
fun1task.start()
fun2task.start()

I get the error: NameError: name myfile is not defined from the line myfile.myFunc() from main.py -> fun1().

How do I enable these two functions defined outside the if __name__=="__main__": block to use the name myfile?

Pass your functions as arguments.

Change your func1 and func2 signatures to:

def fun1(func):
  # Do some processing
  func()

def fun2(func):
  # Do some processing
  func()

And then pass func as an argument:

fun1task = multiprocessing.Process(target=fun1, args=(myfile.myFunc))
fun2task = multiprocessing.Process(target=fun2, args=(myfile.myOtherFunc))