Check if string does not contain strings from the list with wildcard when % symbol in the list value

newlist = ['test', '%ing', 'osh', '16fg']
tartext = 'Singing'

I want to check my tartext value doesn't matching with any value with newlist. if the newlist string contains % symbol in the value then I need to match this as wildcard charecter.

I want to achieve condition as below.

if (tartext != 'test' and tartext not like '%ing' and tartext != 'osh' and tartext != 
'16fg') then return true else false

Since %ing from the lsit contains '%' symbol in it I need to change the comparison as wildcard chatecter search like sql.

In this example 'Singing' is matching with '%ing' then I am expecting the condition to return False.

Below is the code that I have tried but didn't work

import re

newlist = ['test', '%ing', 'osh', '16fg']
tartext = 'Singing'

def wildcard_compare(string, match):
    match = match.replace('%','.*')#.replace('_','.')
    match_expression = f'^{match}$'
    return bool(re.fullmatch(match_expression,string))


def condition_match(lookupstring, mylist):
    for value in mylist:
        if '%' in value:
            if not wildcard_compare(lookupstring,value):
                return True
        else:
            if value != lookupstring:
                return True
    return False

print(condition_match(tartext,newlist))
print(condition_match('BO_IN',['AP_IN','BO_IN','CA_PS']))

Solution

One approach would be to use regular expressions. In this approach, we can replace % in the newlist by .*. Then, use re.search along with a list comprehension to find any matches.

newlist = ['test', '%ing', 'osh', '16fg']
tartext = 'Singing'

newlist = [r'^' + x.replace('%', '.*') + r'$' for x in newlist]
num_matches = sum([1 for x in newlist if re.search(x, tartext)])

if num_matches > 0:
    print("found a match")  # prints here
else:
    print("no matches")

Edit:

See the comment below by @ekhumoro in the case that your input string might also have regex metacharacters in it.