Zsh Variadic Assignment

I want to be able to perform a "variadic assignment" in zsh.

I thought the following would work, but I get parse error near =("${(@)1}")'`:

variadic() {
  local a b
  (a, b)=("${(@)1}")
  echo "$a, $b!"
}

$ variadic Hello world  # Desired output: Hello, world!

(a, b)=($1 $2) results in a similar error.

Thank you

Multi-variable assignment is available in for loops in zsh, so one (unusual-looking) option is to use that and then bypass the loop body:

#!/usr/bin/env zsh

variadic() {
    local a b
    for a b; break
    print -r -- "$a, $b!"
}

variadic Hello world
#=> Hello, world!

variadic Hello world with extra words
#=> Hello, world!

variadic Hello
#=> Hello, !

The function above uses a shortened form of the for loop, and also uses the default list ($@).
This equivalent version has the full loop syntax:

variadicfull() {
    local a b
    for a b in "$@"; do
        break
    done
    print -r -- "$a, $b!"
}

A more conventional assignment also works:

nonvariadic() {
    local a=$1 b=$2
    print -r -- "$a, $b!"
}