linuxbashshell

find 2 exact strings in same line in a file in bash

I have a file called details.txt in bash like below .

1#abc#123#xyz#2024-12-09#2
1#abc#123#xyz_123#2024-12-09#2
1#abc#123#bbc#2024-12-09#2

I am trying to find the line in which a 2 exact strings are present in the same line.

For example:

if the input strings I am passing are abc and xyz then I want the first line as my output

1#abc#123#xyz#2024-12-09#2

But I am getting below as output

1#abc#123#xyz#2024-12-09#2
1#abc#123#xyz_123#2024-12-09#2

But when I pass abc and xyz_123 then I am getting the correct result.

Below is the code snippet of what I have done

wf_name='abc'
session_name='xyz'

# grep session details from batch_details.txt
sess_details=$(grep $wf_name.*$session_name details.txt)

what am I doing wrong here. what is the correct code.

Solution

  • Check this out:

    $ grep "\b${wf_name}\b.*\b${session_name}\b" file
1#abc#123#xyz#2024-12-09#2

    \b is meant for word boundaries

    With awk:

    $ awk -F'#' -v wf=$wf_name -v session=$session_name '$2==wf && $4==session' file
1#abc#123#xyz#2024-12-09#2