I have the following method in a class A in C++ 11 where I know that TMethod gets converted to a typename B<C>.
How can I extract the C typename so that I can access further members from it like in the example below?
template<typename TMethod, typename... Args>
decltype(auto) calledMethod(const Member<TMethod>& method)
{
// somehow extract C from under TMethod
C::Output dummy;
return dummy;
}
You can use a little helper like get_T in the following code that makes it possible to retrieve X from T<X> through class template specialization.
///////////////////////////////////////////////////////////////
template <typename T>
struct get_T;
template <template <typename> class X,typename T>
struct get_T<X<T>> { using type = T; };
///////////////////////////////////////////////////////////////
template<typename T> struct Member {};
struct TMethod { struct Output{}; };
template<typename TMethod, typename... Args>
get_T<TMethod> calledMethod(const Member<TMethod>& method)
{
// somehow extract C from under TMethod
using C = get_T<TMethod>;
typename C::Output dummy;
return dummy;
}
int main() {}