I want a list of directories with the amount of mp3
files in it; then sorted desc - simply to see, which directories contain the most files.
## Relevant command
find . -mindepth 1 -type f -iname "*.mp3" -printf '%P\0' |
awk -F/ -vRS='\0' '{n[$1]++}; END{for (i in n) {printf(n[i]" "i" \n")};}' > ./foo.txt
sort -rno ./foo.txt ./foo.txt
## Full command (output improvements only)
find . -mindepth 1 -type f -iname "*.mp3" -printf '%P\0' |
awk -F/ -vRS='\0' '{n[$1]++}; END{for (i in n) {printf("%03d",n[i]);printf(" ");printf(substr(i,0,60));printf("\n")}; if(length(n)==0) print "NO mp3 found." }' > ./foo.txt
sort -rno ./foo.txt ./foo.txt
./dir_1/fileA.mp3
./dir_2/subdir_1/fileB.mp3
./dir_2/subdir_2/fileC.mp3
./dir_2/subdir_2/fileD.mp3
...
# What I get:
003 dir_2
001 dir_1
# What I want:
002 dir_2/subdir_2
001 dir_2/subdir_1
001 dir_1
It only prints the topmost directories, not the deepest possible. It sums up the mp3 count of subdirs.
I cant increase -mindepth
because the depth varies.
It would be okay to have both, like this:
003 dir_2
002 dir_2/subdir_2
001 dir_2/subdir_1
001 dir_1
I tried the find -links 2
argument but it only works for -type d
not -type f
.
Setup:
mkdir -p dir_{1..2} dir_2/subdir_{1..2}
touch ./dir_1/fileA.mp3 ./dir_2/subdir_1/fileB.mp3 ./dir_2/subdir_2/file{C,D}.mp3
One awk
approach using OP's \0
terminated filenames:
find . -mindepth 1 -type f -iname "*.mp3" -printf '%P\0' |
awk -vRS='\0' '
{ match($0,/\/[^/]+$/) # find last "/" plus file name
count[substr($0,1,RSTART-1)]++ # strip off directory name(s) and use an index in count[] array
}
END {
if (NR==0)
print "NO mp3 found."
else
for (dir in count)
printf "%03d %s\n",count[dir],dir
}'
This generates:
001 dir_1
001 dir_2/subdir_1
002 dir_2/subdir_2
Piping the output to sort -rn
generates:
002 dir_2/subdir_2
001 dir_2/subdir_1
001 dir_1
If we remove all mp3
files and run again this generates:
NO mp3 found.