Suppress receive-job console output when the job uses write-host

I'm starting a job and I need to receive the output before the job finishes. It uses write-host instead of write-output, I know when I use write-output this shouldn't be a problem but assume I need to use write-host.

So as an example I have a job

$job = Start-Job -Name $taskId -ScriptBlock { Write-host "This is the job output, there is a keyword"; start-sleep 2 }

I need to retrieve the console output and check for a keyword there, so I use receive-job

$result = Receive-Job -Job $job -Keep -ErrorAction SilentlyContinue *>&1

I use *>&1 to be able to capture every output. But I need to suppress the console output and only assign the output to the variable. Unfortunately I cannot suppress the console log. Using Out-Null also does not populate the variable.

Is there a way to do this?

Thanks

You may be able to capture the host output from the Job by inspecting the .Information property of the child job. In this case you can also use Receive-Job however the Job host output will still be console output.

$job = Start-Job -Name $taskId -ScriptBlock {
    Write-Host 'This is the job output, there is a keyword'
    Start-Sleep 2
}
$job | Wait-Job | Out-Null
$hostOutput = $job.ChildJobs | ForEach-Object { $_.Information.ReadAll() }