[SOLVED] git push non-current branch, omit remote name

git push non-current branch, omit remote name

Let's say I have:

Two remotes 'remote-A' and 'remote-B'. (in fact the remote names contain long-ish numbers, so really don't want to type or remember them)
Branch 'branch-A' tracking 'remote-A/branch-A'.
Branch 'branch-B' tracking 'remote-B/branch-B'.
Current active / checked-out branch is 'local', so neither 'branch-A' nor 'branch-B'.

I want to push 'branch-A' to 'remote-A/branch-A' without specifying the remote name, and without git checkout branch-A.
How?

Obviously the following would work:

git push remote-A branch-A

But I really want to omit the 'remote-A' part.

Solution

Technically, the remote name and remote ref name are stored in your local configuration:

$ git config --get branch.branch-A.remote
remote-A
$ git config --get branch.branch-A.merge
refs/heads/that/awful/remote/branch/name

Here is a basic script to get the arguments you want for git push:

#/bin/bash

branch=$1

remote=$(git config --get branch."$branch".remote)
remote_ref=$(git config --get branch."$branch".merge)

if [ -z "$remote_ref" ]; then
    echo "*** branch '$branch' has no upstream branch defined, cannot push" >&2
    exit 1
fi

echo "# pushing to $remote $remote_ref ..."
git push "$remote" "$branch":"$remote_ref"

If you name this script git-pushx (<- a name starting with git-, and ending with whatever you want), and place it on your PATH, you can then type:

$ git pushx branch-A
$ git pushx branch-B