I have to interface with a С function, but this code doesn't compile.
// c_enum.h
#pragma once
typedef enum { val1 = 0 } c_style_enum_t;
c_style_enum_t c_func();
// my_class.hpp
#pragma once
extern "С" {
#include "c_enum.h"
}
class my_class {
public:
private:
friend c_style_enum_t ::c_func();
};
Gcc prints an errror:
error: 'enum c_style_enum ' is not a class or namespace
142 | friend c_style_enum ::c_func();
error: ISO C++ forbids declaration of 'c_func' with no type [-fpermissive]
When return type of c_func() is int or some other than enum type this wokrs
How to make this work?
Allowing for your friend
declaration of a "C"
function in the global namespace to work while the "C"
function co-exists with a potential c_func
residing in the same namespace as my_class
, this may be an option:
friend ::c_style_enum_t(::c_func());
Note: This works even without the ambiguity that a c_func
in my_class
's namespace brings too.